log[2](x-4)-log[2](x+4)=3

Solution for log[2](x-4)-log[2](x+4)=3 equation:

Simplifying
log[2](x + -4) + -1log[2](x + 4) = 3

Reorder the terms:
glo * 2(-4 + x) + -1log[2](x + 4) = 3

Reorder the terms for easier multiplication:
2glo(-4 + x) + -1log[2](x + 4) = 3
(-4 * 2glo + x * 2glo) + -1log[2](x + 4) = 3
(-8glo + 2glox) + -1log[2](x + 4) = 3

Reorder the terms:
-8glo + 2glox + -1glo * 2(4 + x) = 3

Reorder the terms for easier multiplication:
-8glo + 2glox + -1 * 2glo(4 + x) = 3

Multiply -1 * 2
-8glo + 2glox + -2glo(4 + x) = 3
-8glo + 2glox + (4 * -2glo + x * -2glo) = 3
-8glo + 2glox + (-8glo + -2glox) = 3

Reorder the terms:
-8glo + -8glo + 2glox + -2glox = 3

Combine like terms: -8glo + -8glo = -16glo
-16glo + 2glox + -2glox = 3

Combine like terms: 2glox + -2glox = 0
-16glo + 0 = 3
-16glo = 3

Solving
-16glo = 3

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Divide each side by '-16lo'.
g = -0.1875l-1o-1

Simplifying
g = -0.1875l-1o-1